- We can apply the fundamental counting principle to multiple selections from the same group.
- In this case, the order in which we place the order matters.
- If we have three groups, to perform, how many ways can we arrange the schedule?
We can choose 1 of 3 for the first slot (3)
We can choose 1 of 2 for the second slot (2)
We can choose 1 of 1 for the third slot (1)
3 x 2 x 1 = 6
- Example: Question 4 page 619
8 x 7 x 6 x 5 x 4 x 3 x 2 = 40,320
- Example
10:
1 choice for the first slot
3 choices for the second slot
2 choices for the third slot
1 choice for the fourth slot
1 choice for the fifth slot
1 x 3 x 2 x 1 x 1 = 6
- These types of problems always involve n x (n-1) x (n-2) x ... x 3 x 2 x 1
- We have a mathematical short hand for this.
- It is called n factorial
- written n!
- 0! = 1
- 1! = 1
- 2! = 2 x 1 = 2
- 3! = 3 x 2 x 1 = 6
- Notice, for n > 1 , n!= n x (n-1)!
- nPr = n!/(n-r)!
- Your calculator should have a n! and a nPr button
learn how to use these.
- Example:
5P3 = 5!/3! = 5x4x3!/3! = 20
- Any questions 13 through 40?
- Example:
42:
10P3 = 10!/3! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3!/3!
= 604,800
- If some items are identical, where order is not noticeable.
- From a set of n items, where p items are identical, q are identical and r are identical then there are
n!
------------
p! x q! x r!
- Example
40
SCIENCE
7 total letters
E is repeated twice
C is repeated twice
S,I,N repeated once.
7!/(2!x2!x1!x1!x1!) = 7!/4 = 1,260