- z = (x-μ)/σ
- A distribution has μ=50 and σ=5, find the z score for
- 45 (45-50)/5 = -5/5 = -1
- 47 (47-50)/5 = -3/5
- 50 (50-50)/5 = 0
- 51 (51-50)/5 = 1/5
- 55 (55-50)/5 = 1
- We use the z score to find the percentage of data between two values.
- We use table 13,7 on page 800 to do this.
- A z score of 1/5 (.2) has a value of A corresponding to .079
- This means that the area under the curve from μ to 1/5 is 0.79
- Or that 7.9% of the population is between the mean and 51.
- To do this
- Draw a picture, put in your scores
- Calculate the z score(s)
- Look up the scores in the table
- Find the area of interest.
- #32
z = 1.19, A = .383
.5 for below the mean plus .383 from mean to position
.883 or 83%
- #34, page 805
z= 2.08 A=.481
To the right of this we need to subtract from .5
.5-.481 =.019
- 40,
between z = -0.15 (A=.060)
and z = -0.82 (A=.294)
Area = .294-.06 = .234
- 56
μ = 1600
σ = 100
More than 1750 hours.
z = x-μ/σ
z = 1750-1600/100 = 150/100 = 1.5
A = .433
So .5-.433 = .067 or 6.7%