Example 2:
Two six sided dice are rolled.
Find the probability for any given number to be the sum
There are 36 ways the dice can be rolled
1: can't happen P(1) = 0
2: Both must be 1 1-1 P(2) = 1/36
3: 1-2, 2-1 P(3) = 2/36
4: 1-3, 2-2, 3-1 P(4) = 3/36
5: 1-4, 2-3, 3-2, 4-1 P(5) = 4/36
6: 1-5, 2-4, 3-3, 4-2, 5-1 P(6) = 5/36
7: 1-6, 6-1, 2-5, 5-2, 3-4, 4-3 P(7) = 6/36
8: 2-6, 3-5, 4-4, 5-3, 6,2 P(8) = 5/36
9: 3-6, 4-5, 5-4, 6-3 P(9) = 4/36
10: 4-6, 5-5, 6-4 P(10) = 3/36
11: 5-6, 6-5 P(11) = 2/36
12: 6-6 P(12) = 1/36
What is the chance of rolling a 7 or 11?
P(7 or 11) = 6/36+2/36 = 8/36 (or 22%)
What are the chances of rolling something other than a 7 or 11
1-P(7 or 11) = 36/36 - 8/36 = 28/36 (or 78%)
What are the odds against rolling a 7 or 11
28/36 ÷ 8/36 = 28/8 or 28 to 8
What are the odds in favor of rolling a 7 or 11
8/36 ÷ 28/36 = 8/28 or 8 to 28