- If we conduct a survey of 60 people
- We find that :
- 42 of them like to go to movies
- 23 of them like to go dancing
- and 12 of them like to do both.
- Then can we figure out:
- How many like dancing but not movies
- How many like movies but not dancing
- How many don't like either.
Let A be the set of people who like the movies
Let B be the set of people who like dancing.
We know n(A) = 42
n(B) = 23
n(U) = 60
n(II) = 12
n(I) = n(A) - n(II)
= 42 - 12 = 30
n(II) = n(B) - n(II)
= 23 - 12
= 11
So the number of people who like movies, dancing or both is
n(I) + n(II) + n(III)
= 30 + 12 + 11
= 53
So the number who don't like either are
n(U) - (n(I)+n(II) + n(III))
= 60 - 53
= 7
- When we have three sets, things get a bit more complicated.
- We usually have more information.
- The number of people in each set
- The number of people in all three sets
- The number of people in any two sets.
- Example: 100 people were asked how they spent their evening
- 34 said that they studied
- 43 said that they watched tv
- 27 said that they chatted with friends
- 7 said that they did all three
- 12 said that they watched tv and studied
- 9 said that they chatted and studied
- 15 said that they chatted and watched tv
- In this case, let:
- A be the set of people who studied
- B be the set of people who watched tv
- C be the set of people who chatted with friends
- The Venn Diagram is somewhat more complex as well.
- What is represented by region V?
- Notice that V is in all three sets
- So it represents people who did all three things.
- so n(V) = 7
- What does II represent
- It is in set A, so they studied
- It is also in set B, so they watched TV
- But it is not in set C, so they did not chat with friends.
- Is this the 12 who said that they studied and watched tv?
- No, that could include people who chatted as well.
- So the 12 who said they studied and watched tv
- So II is really the set who studied and watched TV, but did not chat with friends.
- What represents the 12 people who studied and watched tv?
- That would be everywhere that A and B intersect.
- So that would be II and V
- n(II) + n(V) = 12
- So we can then figure out how many studied and watched tv, but did not chat with friends n(II)
- We can do the same for IV
(people who studied and chatted with friends)
n(IV) + n(V) = 9
n(IV) = 9 - n(V)
= 9 -7
= 2
- And now we can find n(I)
n(A) = n(I) + n(II) + n(IV) + n(V)
34 = n(I) + 5 + 7 + 2
34 = n(I) + 14
34-14 = n(I)
n(I) = 20
so 18 people only studied
- VI can be dealt with as well.
n(VI) + n(V) = 15
n(VI) = 15 - n(V)
= 15 - 7
= 8
- And to finish
n(III) = n(B) - (n(II) + n(V) + n(VI))
= 43 - (5 + 7 + 8)
= 43 - 20
= 23
n(VII) = n(C) - (n(IV) + n(V) + n(VI))
= 27 - (2 + 7 + 8)
= 27 - 17
= 10
n(VIII) = n(U) - (n(I) + n(II) + n(III) + n(IV) + n(V) + n(VI) + n(VII))
= 100 - (20 + 5 + 23 + 2 + 7 + 8 + 10)
= 100 - 75
= 25