Truth Tables for the Conditional and Biconditional
- The truth table for the conditional: (p → q)
p | q | p → q |
---|
T | T | T |
T | F | F |
F | T | T |
F | F | T |
- The book uses the statement, If you get an A, I will buy you a car.
- T → T, If you get an A and I will buy you a car is true.
- F → T, If you don't get an A and I buy you a car is true.
- F → F, If you don't get an A and I don't buy you a car is true.
- T → F, If you get an A but I don't buy you a car is false.
- In other words, the statement is true unless I break my promise.
- Construct a truth table for ~q → ~p
- The truth table for the biconditional (p ↔ q)
p | q | p ↔ q |
---|
T | T | T |
T | F | F |
F | T | F |
F | F | T |
- Construct a truth table for ~p ↔ q
- Construct a truth table for (q↔p)→q
- Construct a truth table for p↔(q∨p)
- A self-contradiction is a compound statement that is always false.
- Construct a truth table for (p↔q)∧(p↔~q), is this a self-contradiction.
- A tautology is a compound statement that is always true.
- Construct a truth table for (p∨q)∨(~p∧~q)
- An implication is a conditional statement that is a tautology.
- Construct a truth table for [(p∧q)∧p]→q
- You will arrive at the office on time if and only if you take back roads, or you won't be able to attend the meeting.
- Give the statement in symbolic form.
- (p↔q)∨r
- Build the truth table.
- Determine if ~p → p is a self-contradiction, tautology, implication or none.
Equivalent Statements
- Two statements are equivalentA ⇔B if both have exactly the same truth table values in the answer columns of the truth tables.
- are p∨q and ~(~p∧~q) equivalent?
- are ~p∧~q and ~(p∧q) equivalent?
- DeMorgan's laws state
- ~(p∧q) ⇔ ~p∨~q
- ~(p∨q) ⇔ !p∧~q
- Negate the statement: "It is not true that streets are dangerous or there is an ice storm."
- Negate the statement: "The bus does not have an engine or the people do not have money"