inorder = true (1) [1] i=0; (1) [1] top: if(i>arraysize) goto out (2) [size+1] if (array[i] > array[i+1] goto next (4) [size] inorder = false (1) [?] next: i = i + 1 (2) [size] goto top (1) [size] out: We can assume either i: the array is in order and the 5th statement is always executed. ii: the array is not in order and the 5th statement is never executed. iii: Something inbetween. Execution time = 1*1+1*1 + 2*(size+1) + 4*size+ 0*1 + 2*size + 1*size = 4+9*size or = 4+10*size or = 4+9.5*size