Boolean Evaluation

• Caution comparing floats
  • boolvar = 0.33333 == 1.0/3.0;
  • Solution: boolvar = fabs(0.33333 - 1.0/3.0) < 0.001
• Short-circuit evaluation
  • boolvar = ((x < 10) && (y >5))
  • boolvar = ((x< 10) || (y > 5))
  • When can each stop early
• Operator Precedence

  • Highest (Done First)	!, Unary +, Unary -
    	*, /, %
    	+, -
    	<, <=, > >=
    	==, !=
    	&&
    	||
    Lowest (Done Last)	=