$\require{cancel}$
a+ab = a(1+b) = a(1) = a
a + ab = a(b + b) + ab = ab + ab + ab = ab + ab + ab + ab = ab + ab + ab + ab = a(b + b) + b(a + a) = a(1) + b(1) = a b
a(a+b) = aa + ab = a + ab = a (first proof)
(a+b)(a+b) = aa + ab + ab + bb = a + ab + ab + 0 = a + a(b + b) = a + a(1) = a + a = a